lundi 7 novembre 2016

using a random number as a parameter to generate a random number

Im not sure of this is an acceptable post, but out of curiosity would

Random rnd = new Random();
        int random1 = rnd.Next(1, 24);
        int random2 = rnd.Next(25, 49);

        int random3 = rnd.Next(random1, random2);

        int random4 = rnd.Next(50, 74);
        int random5 = rnd.Next(75, 100);

        int random6 = rnd.Next(random4, random5);

        int random7 = rnd.Next(random3, random6);
        Console.WriteLine(random7);

be more of a random number than just say

Random rnd = new Random();
int random1 = rnd.Next(1, 100);
Console.WriteLine(random1);




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