Peek at a value from an array with a probabilistic quantity

I have an array of 10 elements.

|1|2|3|4|5|6|7|8|9|10|

The idea is to randomly peek at a value from this array, but with some probabilistic quantity.

The probabilistic selection of the element is as follows:

|5%|10%|15%|30%|20%|4%|6%|1%|3%|7%|

This means that selecting the first element has a 5% chance, the second element has a 10% chance and so on.

My Solution:

import java.util.*;

public class Example {
     public static void main( String[] args ) {

         int [] values = {1,2,3,4,5,6,7,8,9,10};
         double [] probabilities = {0.05,0.1,0.15,0.3,0.2,0.04,0.06,0.01,0.03,0.07};


         double cumulativeSum = 0;
         double r = new Random().nextDouble();//random number between 0 and 1
         int index=0;// index of the chosen value
         for (double prob:probabilities) {
             cumulativeSum += prob;
             if (cumulativeSum >= r) {
                 break;
             }
             index++;
         }
         System.out.println(index);
         System.out.println("the value picked "+values[index]);

     }
}

I'm looking for a faster solution than mine.