Python Monopoly Dice

i try to make a dice in python where it allows up to 3 dice if it is 3 times the same the player will go to jail. but i'm stuck with the actions at counter 2 where it will reply go back to jail instead of printing it one million times what is happening with my console right now every time. and if i insert the break on the correct place it wont print out 1 + 1 = go directly to jail instead it completely ignores that statement. can someone please help me.

import random

def monopolyworp():
    counter = 0
    while True:
        d1 = random.randint(1,7)
        d2 = random.randint(1,7)
        # d1 = 3
        # d2 = 3
        # lst = d1,d2
        print(f"{d1}+{d2}={d1+d2}")
        if d1 == d2:
            counter += 1
            continue
        if counter == 2:
            a = d1
            b = d2
            x = d1,d2
            if a == b:
                print(f"{a} + {b} = direct naar de gevangenis")
                break
            elif a != b:
                print(f"{a}+ {b} = {sum(x)}")
                break
monopolyworp()

output has to be:

>>> monopolyworp() 
1 + 2 = 3
[(1, 2)] 
>>> monopolyworp() 
4 + 4 = 8
4 + 5 = 9
[(4, 4), (4, 5)]
>>> monopolyworp() 
3 + 3 = 6
4 + 4 = 8
1 + 1 = direct naar gevangenis
[(3, 3), (4, 4), (1, 1)]
>>> monopolyworp() 
3 + 3 = 6
4 + 4 = 8
1 + 2 = 3
[(3, 3), (4, 4), (1, 2)]