random.choice() equivalent in order

I know using for loops display the items in a list in order, but it only displays them at once.

e.g.:

>>> list = [1,2,3,4,5]
>>> for i in list:
...     print(i)
...
1
2
3
4
5

Same if I do it with range and length, regarding indexes.

But what random.choice() does is taking a random item in the list and then printing it each time the function is called.

e.g.:

>>> from random import choice
>>> list = [1,2,3,4,5]
>>> print(choice(list))
1
>>> print(choice(list))
5
>>> print(choice(list))
4

Is there an equivalent to random.choice() but for printing the items in lists in order each time it is required?

Like:

>>> list = [1,2,3,4,5]
>>> print(function(list))
1
>>> print(function(list))
2
>>> print(function(list))
3

And so on.