Generate N random numbers with 2 decimals that sums up to a M number

So, the idea that I have is to be able to divide $2.00 into 10 person, and each of them will receive $x.xx amount of money randomly. (N and M will always limited to 2 decimals and > 0)

Ex: {0.12, 0.24, 1.03, 0.01, 0.2, 0.04, 0.11, 0.18, 0.05, 0.02}

Currently I have tried:

private static BigDecimal[] randSum(int n, double m)
{
    Random rand = new Random();
    BigDecimal randNums[] = new BigDecimal[n], sum = new BigDecimal(0).setScale(2);

    for (int i = 0; i < randNums.length; i++)
    {
        randNums[i] = new BigDecimal(rand.nextDouble()).setScale(2, RoundingMode.HALF_EVEN);
        sum = sum.add(randNums[i]);
    }

    for (int i = 0; i < randNums.length; i++)
    {
        BigDecimal temp1 = randNums[i].divide(sum, 2, RoundingMode.HALF_EVEN);
        BigDecimal temp2 = temp1.multiply(new BigDecimal(m).setScale(2));
        randNums[i] = temp2;
    }

    return randNums;
}

public static void main(String[] args)
{
    BigDecimal d[] = randSum(5, 2);

    double sum = 0;
    for (BigDecimal n : d)
    {
        sum += n.doubleValue();
        System.out.println(n);
    }
    System.out.println("total: " + sum);
}

But BigDecimals are too confusing and they don't add up. Sometimes the total is 1.98 or 2.01. Doubles doesn't work because of the Double-precision floating-point.

The code was taken from:

Getting N random numbers that the sum is M