Given a target matrix size of N rows and M columns, is it possible to pick values such that all rows and columns sum to 1, on the condition that the matrix is not symmetric across the diagonal? Here's a target matrix I was able to generate when N==M (The problems arise when N!=M - see below):
[[0.08345877 0.12844672 0.90911941 0.41964704 0.57709569]
[0.53949086 0.07965491 0.62582134 0.48922244 0.38357809]
[0.80619328 0.27581426 0.31312973 0.26855717 0.4540732 ]
[0.11803505 0.88201276 0.1990759 0.2818701 0.63677383]
[0.57058968 0.75183898 0.07062126 0.6584709 0.06624682]]
I'm writing this in numpy. Currently I've written the following (brute force) code, which I know works when n==m. However, if n != m, rowwise and columwise sums don't converge to 0, and the ratio of rowwise sums to columwise sums converges to (n/m):
n,m = (5,4)
mat = np.random.random((n,m))
for i in range(100):
s0 = mat.sum(0)
s1 = mat.sum(1)[:,newaxis]
mat = (mat/s0)
mat = (mat/s1)
if i%10 == 0:
print(s0[0]/s1[0,0])
The final output in this case is 1.25 (I.e. n/m, or 5/4). I'm beginning to think this might not be mathematically possible. Can someone prove me wrong?
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