This question has been asked before, but I've never really seen a good answer.
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I want to generate 8 random numbers that sum to 0.5.
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I want each number to be randomly chosen from a uniform distribution (ie, the simple function below will not work because the numbers will not be uniformly distributed).
def rand_constrained(n,tot): r = [random.random() for i in range(n)] s = sum(r) r = [(i/s*tot) for i in r] return r
The code should be generalizable, so that you can generate N uniform random numbers that sum to M (where M is a positive float). If possible, can you please also explain (or show with a plot) why your solution generates random numbers uniformly in the appropriate range?
Related questions that miss the mark:
Generate multiple random numbers to equal a value in python (current accepted answer isn't uniform--another answer which is uniform only works with integers)
Getting N random numbers that the sum is M (same question in Java, currently accepted answer is just plain wrong, also no answers with uniform distribution)
Generate N random integers that sum to M in R (same question, but in R with a normal--not uniform--distribution)
Any help is greatly appreciated.
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