Can this code be reverse-engineered to find the random seed?

local digits = {'1', '2', '3', '4', '5', '6', '8', '9'} 
math.randomseed(os.time()) 
local result = digits[math.random(8)] 
for i = 2, 50 do 
    result = result..digits[math.random(8)] 
end 
print(result)

--> 88854243421464255299891111895292628431988589634664

This is a Lua script designed to spit out fifty random digits, excluding 0 and 7. I can't seem to find the Lua randomness algorithm. Is it possible to find the value returned by os.time()?

To put it in layman's terms, here's how the script works:

1. Define a list of eight single-character strings.
2. Seed the pseudo-random algorithm with the number of seconds since midnight on January 1, 1970.
3. Select a number between one and eight using the pseudo-random algorithm, then use that to select an item from the list. E.g. the number selected is seven, the algorithm picks the seventh item in the list.
4. Add that item onto the end of the result. Repeat until the result is fifty digits long.

So because seven is left out, the random algorithm really spit this out:

77754243421464255288781111785282627431877578634664

But because seven is missing, seven and eight became eight and nine, yielding this:

88854243421464255299891111895292628431988589634664

To clarify, I'm trying to figure out how the random algorithm works to find the key that was entered as a random seed.

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