Numpy allows me to easily sample s
numbers from a range of 0,...,M-1
without replacement, for example this way:
numpy.random.choice(5, 3, replace=False) # sampling for M=5 and s=3
However, how do I do this independently N times?
If I were to write a loop by hand in Python, it would look like this:
N = 10
res = []
for i in range (0, N):
res.append(numpy.random.choice(5, 3, replace=False)
However, it is best to avoid writing any loops in Python in favor of vectorizing computations using numpy facilities, since this offers much better performance.
Therefore, how to independently sample s
numbers without replacement N
times from a range of 0,...,M-1
in numpy?
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