Picking a random number from a list of floating numbers [on hold]

I am trying to compare the value of two statutes(open,closed) for 3 times,the values of "OPEN"s with value of "CLOSED"s in my list, and count how many times the value of "OPEN"'s are higher than "CLOSED"'s. For its details:

try.txt

OPEN    1
CLOSED  4.2
OPEN    2.755
CLOSED  -2.7
CLOSED  27
CLOSED  0.344
CLOSED  -0.93

However, I am having an error when random.choice picks a floating number from the values:

TypeError: object of type 'float' has no len()

I see that random wants to pick integers as len() function does not apply to floating numbers. My trial is:

 #!/usr/bin/env python

import string
import random

with open('try.txt', 'r') as f:
    data = [f.strip('\n').split('\t') for f in open('try.txt')]
    print data
    for stat,value in data:
        #print stat
        #print float(value)
        randomvalue= random.choice((float(value)))
        print randomvalue, "random"
        if str(stat)== "OPEN":
            print value,"IS THE VALUE OF OPEN"
            openvalue = value
            #print openvalue
            count = 0
            n = 0
            while n < 3 :
                if float(openvalue) > float(randomvalue):
                     print "OPENISBIGGER"
                     count = count + 1
                     n = n + 1
                print n, count

If I change the float(random.choice) to random.choice only, I receive this output which takes the - of minus values, and . of decimals:

1 random

1 IS VALUE OF OPEN
3 0
. random
5 random
2.755 IS VALUE OF OPEN
3 0
- random
2 random
4 random
. random

How do I get pass it?