import numpy as np
c = np.random.random()
Then we know c is uniformly distributed over the half-open interval [0,1) and the probability density function (pdf) of c is given by, p(c) = 1/(1-0) for 0 <= c < 1.
Now, if generated d as follows:
scalar = 30
d = scalar * np.random.random()
then what is the pdf of d i.e. p(d)?
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