jeudi 5 novembre 2020

Randomly getting value with percentage of chance in Java

I would like to be able to return (and in our case, for the example, display) an item of an enumeration, according to a certain predefined percentage of chance for each item. An illustration in code of this enumeration just below :

package me.lucas.test;

public enum Item {

    ITEM_1("Item 1", 30),
    ITEM_2("Item 2", 30),
    ITEM_3("Item 3", 10),
    ITEM_4("Item 4", 65);

    private final String name;
    private final int percentage;

    Item(String name, int percentage) {
        this.name = name;
        this.percentage = percentage;
    }

    public String getName() {
        return name;
    }

    public int getPercentage() {
        return percentage;
    }

}

Also, these items will be stored in a List.

package me.lucas.test;

import java.util.ArrayList;
import java.util.List;

public class Program {

    private final List<Item> items = new ArrayList<>();

    /**
     * Displays an item among those in the list, according to their percentage chance of appearing.
     * @param items The items
     */
    public void displayItem(List<Item> items) {
        Item item;

        item = ?

        System.out.println("Selected item : " + item.getName() + " with percentage : " + item.getPercentage());
    }

}

Namely that, as in this example, two items can have the same percentage of chance to appear.

I also looked at the following topic (Java Random Percentage Chance) but in my case, the percentages are not predefined in the expressions directly but in the enumeration.

So I would appreciate your help. Thank you in advance for taking the time to help me.




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