Pick a balance number of odd and even numbers in python

I need help please. I have this program.

col1 = [1,2,3,4,5,6,7,8,10,13,16]
col2 = [2,4,5,6,7,9,11,13,14,15,17,18,19,20,21,22] 
col3 = [7,8,10,12,13,14,15,16,17,18,19,23,24,25,27,29,30] 
col4 = [9,12,17,18,19,20,22,23,24,25,26,28,30,31,33] 
col5 = [20,21,24,25,26,28,30,32,33,34,35] 
b1 = [1,3,5,7,8] 
b2 = [2,4,6,7,9,10,11,12] 

def pickem():
    pick1 = random.choice(col1)
    pick2 = random.choice( [i for i in col2 if i > pick1] )
    pick3 = random.choice( [i for i in col3 if i > pick2] )
    pick4 = random.choice( [i for i in col4 if i > pick3] )
    pick5 = random.choice( [i for i in col5 if i > pick4] )

    bonus1 = random.choice(b1)
    bonus2 = random.choice(b2)

    return (pick1,pick2,pick3,pick4,pick5,bonus1,bonus2)

print( pickem() )

I would like the picked number to have a sum total of 3 odd numbers. Is there a way I can do that? It is choosing random numbers from the list I provided above but it will check to see how many of them are odd and if there are less than 3 or whatever amount I put it will pick again until there are 3 odd numbers in total, but only in col1 - col5. So though the final number are seven digits long, I only want to the first 5 digits to have a total of 3 odds. Thank you for your help.