bytes how many combinations calculation

Given the following code snippet

SecureRandom generator = new SecureRandom();
byte[] randomBytes = new byte[6];
generator.nextBytes(randomBytes);

How many combinations are there? And how do you work it out?

My current thinking is that it works like the following

byte[6]. creates an array of 6 bytes. Each byte of 8 bits. So in total that has 256 combinations. 2^8

So if you expand that to 6 bytes then you can do 256^6. 281,474,976,710,656

Have I got this right and answered my own question or have I missed something?