How to Loop a Function in Python Without a Clear Variable

Below is code that correctly outputs a random password based on the sequence, using multiple for loops. I want to loop the function 10 times to output 10 passwords, but I can't seem to figure out what variable to loop in this case.

import random
letters = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z', 'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J','K','L','M','N','O','P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
numbers = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9']
symbols = ['!', '#', '$', '%', '&', '(', ')', '*', '+']

print("Welcome to the PyPassword Generator!")
num_letters= random.randint(3, 6)
num_numbers = random.randint(1, 4)
num_symbols = (10 - num_letters - num_numbers)
print(f'Your requested {num_letters} letters, {num_numbers} numbers, and {num_symbols} symbols:')
password_list = []
for num in range(num_letters):
`letter = random.choice(letters)`    
`password_list.append(letter)`
for num in range(num_numbers):
`number = random.choice(numbers)`
`password_list.append(number)`
for num in range(num_symbols):
`symbol = random.choice(symbols)`
`password_list.append(symbol)`
random.shuffle(password_list)
password = ''   

for char in password_list:
`password = password + char`

print(password)