I have some Java code. In my code, I have a collection of users. Each user has a percentage chance of "winning" the collection, as that the sum of the chance of each user in the collection is 100. To choose a winner, I sort the collection (which is an array) in ascending order. My problem is choosing the winner based off of that sorted array. This is what I have tried:
public Bet getWinner() {
double random = Math.random() * 100;
Bet[] copy = Arrays.copyOf(getBets(), bets.size());
Arrays.sort(copy);
for (Bet bet : copy) {
if (random < getChance(bet)) {
return bet;
}
}
return null;
}
public float getChance(Bet bet) {
return (bet.getAmount() / getJackpotTotal()) * 100;
}
public float getJackpotTotal() {
float total = 0;
for (Bet bet : getBets()) {
total += bet.getAmount();
}
return total;
}
But is there are two users in the collection, one with 10% chance of winning and the other with 90%, if random
is > 90, getWinner
returns null
. How else can I do this? Is there a way to create a random distribution based off of a percentage, or is there something simpler or different?
Thanks for your help.
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