Python - Generate random list of 2-dimesional float values

I want to generate a very long list of random two dimensional coordinates (floats) between 0.0 and 1.0.

Do you know a faster code than this (on my computer it takes about 4.1 sec for 10**7 coordinates)?:

coordinates = (np.random.randint(0,10,(10**7,2))/10.).tolist()

For this number I can wait, but what should I do when the number of coordinates is 10**9?

Timing for 10**7:

import numpy as np
import timeit


def createCoordinates(num_coord):
    return (np.random.randint(0, 10, (num_coord, 2))/10.).tolist()


def checkElapsedTime(num_runs):
    t_elapsed = np.empty(num_runs, dtype=np.float)
    for i in range(num_runs):
        t_start = timeit.default_timer()
        coordinates_2d = createCoordinates(10**7)
        t_elapsed[i] = timeit.default_timer()-t_start
        print('run: %2d, time_elapsed = %4.3f sec' % (i, t_elapsed[i]))

    print('(mean \u00B1 standard deviation): elapsed time = %4.3f sec \u00B1 %5.4f sec' % \
            (np.mean(t_elapsed), np.std(t_elapsed)))
     
checkElapsedTime(10)

run:  0, time_elapsed = 5.335 sec
run:  1, time_elapsed = 4.511 sec
run:  2, time_elapsed = 1.907 sec
run:  3, time_elapsed = 4.159 sec
run:  4, time_elapsed = 4.193 sec
run:  5, time_elapsed = 4.239 sec
run:  6, time_elapsed = 4.209 sec
run:  7, time_elapsed = 4.189 sec
run:  8, time_elapsed = 4.273 sec
run:  9, time_elapsed = 4.329 sec
(mean ± stdandard deviation): elapsed time = 4.134 sec ± 0.8139 sec