How do I pass a vector into cpp discrete_distribution?

cxx_std 14

I need to create a random number generator whose distribution matches a given histogram. The values of the histogram are stored in a file.

std::random_device rd;
std::default_random_engine dre(rd());
std::vector<int> weights;

// these histogram numbers will be read from a file (about 400 of them)
weights.push_back(10);
weights.push_back(20);
weights.push_back(30);
weights.push_back(40);
weights.push_back(10);

std::discrete_distribution<int> discrete_dist(weights); // this is line saying that it doesn't know how to take a vector like a good bi**h
G4double random_number;
for(int n=0; n < 1000; ++n) {
    random_number =
        min_num + ((discrete_dist(dre) + 1) * (max_num - min_num) / intervals_count );
    random_numbers->push_back(random_number);

error on compilation.

error: no matching function for call to 'std::discrete_distribution<int>::discrete_distribution(std::vector<int>&)'
   32 |     std::discrete_distribution<int> discrete_dist(weights);

This is how the documentation says it is to be done.

#include <iostream>
#include <map>
#include <random>
 
int main()
{
    std::random_device rd;
    std::mt19937 gen(rd());
    std::discrete_distribution<> d({40, 10, 10, 40});
    std::map<int, int> m;
    for(int n=0; n<10000; ++n) {
        ++m[d(gen)];
    }
    for(auto p : m) {
        std::cout << p.first << " generated " << p.second << " times\n";
    }
}

It seems weird that this could only be used by hardcoding the distribution. Any help will be appreciated, thank you.

PS: typecasting to std::discrete_distribution<int>::param_type did not help as it didn't know how to convert vector to that.