Ok, so i been working on this right here that is intended to be part of a encryption software that works synonymously like 2fa
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <ctime>
using namespace std;
int main()
{
int RGX;
int box[32];
srand (time(NULL));
RGX = rand() % 100000000 + 9999999;
cout << "Random Generated One Time HEX #:" << endl;
cout << std::hex << RGX << endl;
while(RGX!=1 || 0)
{
int m = RGX % 2;
cout << " " << m << " ";
RGX = RGX / 2;
cout << RGX << endl;
}
return 0;
}
Here is a sample of what it outputs:
Random Generated One Time HEX #:
3ff3c70
0 1ff9e38
0 ffcf1c
0 7fe78e
0 3ff3c7
1 1ff9e3
1 ffcf1
1 7fe78
0 3ff3c
0 1ff9e
0 ffcf
1 7fe7
1 3ff3
1 1ff9
1 ffc
0 7fe
0 3ff
1 1ff
1 ff
1 7f
1 3f
1 1f
1 f
1 7
1 3
1 1
** Process exited - Return Code: 0 **
The result is different each time since it's randomized, i'm still not finished. But what i need to know is how do i store the binary value in an array, the binary value are the numbers on the left.
Aucun commentaire:
Enregistrer un commentaire