I have earlier written a code that generates random number - 0 or 1 - that represents the outcome of a one toss, with the assumption that probability to have head or tail is 0.5 " equal probabilities".
Now I want to modify the code so that, it will represent a Bernolli trial. H - head- represents a success, and a variable p represents probability of success. I tried to search how to generate random number with specific probability however I didn't know exactly how it's done.
My Earlier Code
n = 1; %number of trials
% Generating a random number from 1 to n trials, logical condition <0.5
% indicates that function rand should generates only two outcomes,
% either 0 or 1.
% Let 1 indicates "H" and 0 indicates "T".
x = rand(1,n) <0.5;
% count how many H and T in each tossing trial
number_of_H =0 ; number_of_T =0;
for n=1:n
if(x(1,n)==1)
number_of_H=number_of_H+1;
end
if(x(1,n)==0)
number_of_T = number_of_T+1;
end
end
probability_H = number_of_H/n;
probability_T = number_of_T/n;
I have seen this r = random(pd) from mathwork reference but when I tried to replace 0.7 with pd as a probability it gives an error that this is not a probability distribution.
Aucun commentaire:
Enregistrer un commentaire