Count the number of occurrences in an array with random numbers without methods or list in C#

I am trying to solve an exercise in C# as follows:

Write a program that generates 20 random integers between 0 and 9 and displays the count for each number. Use an array of ten integers, say counts, to store the counts for the number of 0s, 1s, ..., 9s.)

This is what i come up with which kind of work but i have a problem with the 0's counting 1 extra all the time.

using System.Collections.Generic;
using System.Text;

namespace ArrayExercises
{
    class TaskFive
    {
        public static void FindNumberCount()
        {

            int c0=0,c1=02,c2=0,c3=0,c4=0,c5=0,c6=0,c7=0,c8=0,c9=0;
            int[] arr = new int[20];
            Random rand = new Random();
            Console.WriteLine("Numbers generated ");
            for (int i = 0; i < 19; i++)
            {
                arr[i] = rand.Next(0, 10);
                Console.WriteLine(arr[i]);
            }
            foreach(int number in arr)
            {
                 if (number == 0) { c0++; }
            else if (number == 1) { c1++; }
            else if (number == 2) { c2++; }
            else if (number == 3) { c3++; }
            else if (number == 4) { c4++; }
            else if (number == 5) { c5++; }
            else if (number == 6) { c6++; }
            else if (number == 7) { c7++; }
            else if (number == 8) { c8++; }
            else if (number == 9) { c9++; }

            }
            Console.WriteLine
            (
              $"Number of 0's: {c0} \n" +
              $"Number of 1's: {c1} \n" +
              $"Number of 2's: {c2} \n" +
              $"Number of 3's: {c3} \n" +
              $"Number of 4's: {c4} \n" +
              $"Number of 5's: {c5} \n" +
              $"Number of 6's: {c6} \n" +
              $"Number of 7's: {c7} \n" +
              $"Number of 8's: {c8} \n" +
              $"Number of 9's: {c9}"
            );
        }
    }
}

Thanks in advance :)